字符串分隔成数组

Question

问题描述字符串分隔成数组，由于空格处过多，没有特别好的思路当前实现方法我觉得现在的实现方法实在有点麻烦varstr='sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737'vararr=str.split('')varnewArr=['']arr.forEach(item=>{letoldValue=newArr[newArr.length-1].trim()if(item==='&&'||item==='||'){newArr.push(item)}else{newArr[newArr.length-1]=oldValue+''+item}})相关代码'sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737'你期待的结果是什么？实际看到的错误信息又是什么？["sourceIp==86.248.198.93","&&sourceIp!=86.248.198.93","||sourceIp==86.248.198.93","||sourceIp!=86.248.198.93","&&sourceIp==86.248.198.93:737","&&sourceIp!=86.248.198.93:737","||sourceIp==86.248.198.93:737","||sourceIp!=86.248.198.93:737"]

Answer 1

varstr='sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737';
consts=str.split(/\s*(?=\|{2}|\&{2})/);
console.log(s);
                            

Answer 2

要这样？
conststr='sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737'
constarr=str.split(/\s+(?:&&|\|\|)\s+/)
console.log(arr)