请各位大佬指点！如何根据某字段分级普通数组，并重组成复合数组？感激不尽

Question

现在有一个包含了多级网点的数组，想根据这个数组中的网点等级level字段进行数组分级重组，目标是重组成一个复合数组。原数组代码如下：list:[{"id":30064771072,"lastModified":"2019-02-1320:14:42:000","userCount":4,"deviceCount":4,"level":0,"name":"测试网点11"},{"id":30081548288,"lastModified":"2019-01-3014:36:33:729","userCount":0,"deviceCount":0,"level":1,"name":"不过去"},{"id":30081679360,"lastModified":"2019-01-3014:23:33:345","userCount":0,"deviceCount":0,"level":2,"name":"120的子网点"},{"id":30081744896,"lastModified":"2019-01-3006:52:07:915","userCount":0,"deviceCount":0,"level":2,"name":"360"},{"id":30098325504,"lastModified":"2019-01-2909:52:27:640","userCount":0,"deviceCount":0,"level":1,"name":"120"},{"id":30131879936,"lastModified":"2019-01-2910:14:03:897","userCount":0,"deviceCount":0,"level":1,"name":"规划"},{"id":30148657152,"lastModified":"2019-01-3002:44:48:868","userCount":0,"deviceCount":0,"level":1,"name":"小唐"},{"id":30165434368,"lastModified":"2019-01-3014:39:28:452","userCount":0,"deviceCount":0,"level":1,"name":"任务少"},{"id":30182211584,"lastModified":"2019-01-3015:32:40:672","userCount":0,"deviceCount":0,"level":1,"name":"氧化铝"},{"id":30215766016,"lastModified":"2019-01-3015:33:17:230","userCount":0,"deviceCount":0,"level":1,"name":"不过呢"},{"id":30232543232,"lastModified":"2019-01-3007:35:41:689","userCount":0,"deviceCount":0,"level":1,"name":"77"},{"id":30249320448,"lastModified":"2019-01-3008:30:30:981","userCount":0,"deviceCount":0,"level":1,"name":"33344"},],level是网点等级字段，有0，1，2，3这四级。目标数组就是根据这个分级目标数组代码如下：listBox:[{//存放所有数组id:'',name:'',lastModified:'',userCount:'',deviceCount:'',children:[{//存放一级网点数组id:'',name:'',lastModified:'',userCount:'',deviceCount:'',maxList:[{//存放二级网点数组id:'',name:'',lastModified:'',userCount:'',deviceCount:'',minList:[]//存放三级网点数组}]}]}],我本来打算用for循环嵌套if实现，实现的时候进行了多次修改最终实现代码如下：for(leti=0;i

Answer 1

这种一般来说会有两个id，一个是自己的id，一个是父级的id。这样来合并。
你现在这个没啥意思啊，不适合你那种结构。
适合如下结构,按level,push到不同的数组就完事了。
{
0:[{}],
1:[{},{}],
2:[{},{}],
3:[{},{}],
}
然后可以遍历上面那个结构，把1加到0[0]的matList上。。。。
                            

Answer 2

根据上楼所说补充：level=0，有几个？如果只有一个就可以把筛选的level=1push进去。level=1，有多个？那根据那个字段吧level=2的数据对应到level=1的数据中。它不适合你想要的结构