在线等，挺急的！如何用空数组，补齐数组数量十分感谢

Question

test=[["qwe","1"],["ewq","2"],["aaa","4"],]我想让数组数量保持在四个，有缺就补空数组，并且要照数组内的数字去补，却哪里补哪里补完要像这样test=[["qwe","1"],["ewq","2"],["",""],["aaa","4"],]该如何实现这需求?

Answer 1

lettest=[
["qwe","1"],
["ewq","2"],
["aaa","4"],
]
functionsetArr(test){
for(leti=0;iconstitem=test[i];
if(i+1!=item[1]){
test.splice(i,0,['',''])
}
}
returntest
}
console.log(setArr(test))
                            

Answer 2

test.reduce((acc,cur,i)=>{
while(cur[1]-1!=i){
acc.push(['','']);
i++
}
acc.push(cur);
returnacc;
},[])
前提默认原数组是按循序(1,2,3...)排列的