大佬们遇到过这个问题吗？一道前端面试题

Question

题目描述有一个树形结构：vardata={key1:'str1',key2:{key3:'str3',key4:'str4',key5:{key6:'str6'},key8:{key9:'str9'}},key7:"str7"//...}实现一个方法getKeys(data,str),获取字符串str在data中所有的上级节点名称，例如：getKeys(data,'str1')返回'key1'getKeys(data,'str3')返回'key2key3'getKeys(data,'str6')返回'key2key5key6'

Answer 1

functiongetKeys(data,str){
varresult=[];
functionrecursion(data,str){
for(varkeyindata){
if(data[key]==str){
result.push(key);
returnresult;
}
if(typeofdata[key]=='object'){
result.push(key);
returnrecursion(data[key],str)
}
}
}
recursion(data,str);
returnresult.join('');
}
                            

Answer 2

varresult=[]
constGetKey=(data,key)=>{
for(letvindata){
if(data[v]==key){
result.push(v)
returnresult
}
if(typeofdata[v]=='object'){
result.push(v)
returnGetKey(data[v],key)
}
}
}