JS两个对象数组，如何根据元素的值，去除其中一个数组没有的元素

Question

constarray1=[{currency:'CNY',value:1},{currency:'USD',value:2}]constarray2=[{currency:'CNY',value:332},{currency:'USD',value:424},{currency:'HK',value:123}]数组array1和array2,现在需要根据array1子元素的currency字段，删除array2中多余的子元素，即得到constarray2=[{currency:'CNY',value:332},{currency:'USD',value:424}]怎么写啊，，想了好久都没实现~~~!!!!

Answer 1

letresult=array2.filter(item=>array1.some(value=>value.currency==item.currency))
                            

Answer 2

constcurrency=array1.map(item=>item.currency)
array2.filter(item=>currency.includes(item.currency))