3 回答
TA贡献1851条经验 获得超4个赞
如果允许使用LINQ,请查看以下示例。它创建两个带有整数列的DataTables,用一些记录填充它们,使用LINQ查询连接它们并将它们输出到Console。
DataTable dt1 = new DataTable();
dt1.Columns.Add("CustID", typeof(int));
dt1.Columns.Add("ColX", typeof(int));
dt1.Columns.Add("ColY", typeof(int));
DataTable dt2 = new DataTable();
dt2.Columns.Add("CustID", typeof(int));
dt2.Columns.Add("ColZ", typeof(int));
for (int i = 1; i <= 5; i++)
{
DataRow row = dt1.NewRow();
row["CustID"] = i;
row["ColX"] = 10 + i;
row["ColY"] = 20 + i;
dt1.Rows.Add(row);
row = dt2.NewRow();
row["CustID"] = i;
row["ColZ"] = 30 + i;
dt2.Rows.Add(row);
}
var results = from table1 in dt1.AsEnumerable()
join table2 in dt2.AsEnumerable() on (int)table1["CustID"] equals (int)table2["CustID"]
select new
{
CustID = (int)table1["CustID"],
ColX = (int)table1["ColX"],
ColY = (int)table1["ColY"],
ColZ = (int)table2["ColZ"]
};
foreach (var item in results)
{
Console.WriteLine(String.Format("ID = {0}, ColX = {1}, ColY = {2}, ColZ = {3}", item.CustID, item.ColX, item.ColY, item.ColZ));
}
Console.ReadLine();
// Output:
// ID = 1, ColX = 11, ColY = 21, ColZ = 31
// ID = 2, ColX = 12, ColY = 22, ColZ = 32
// ID = 3, ColX = 13, ColY = 23, ColZ = 33
// ID = 4, ColX = 14, ColY = 24, ColZ = 34
// ID = 5, ColX = 15, ColY = 25, ColZ = 35
TA贡献1815条经验 获得超10个赞
我想要一个连接表的函数,而不需要使用匿名类型选择器定义列,但很难找到任何。我最终不得不自己做。希望这将有助于将来搜索此内容的任何人:
private DataTable JoinDataTables(DataTable t1, DataTable t2, params Func<DataRow, DataRow, bool>[] joinOn){ DataTable result = new DataTable(); foreach (DataColumn col in t1.Columns) { if (result.Columns[col.ColumnName] == null) result.Columns.Add(col.ColumnName, col.DataType); } foreach (DataColumn col in t2.Columns) { if (result.Columns[col.ColumnName] == null) result.Columns.Add(col.ColumnName, col.DataType); } foreach (DataRow row1 in t1.Rows) { var joinRows = t2.AsEnumerable().Where(row2 => { foreach (var parameter in joinOn) { if (!parameter(row1, row2)) return false; } return true; }); foreach (DataRow fromRow in joinRows) { DataRow insertRow = result.NewRow(); foreach (DataColumn col1 in t1.Columns) { insertRow[col1.ColumnName] = row1[col1.ColumnName]; } foreach (DataColumn col2 in t2.Columns) { insertRow[col2.ColumnName] = fromRow[col2.ColumnName]; } result.Rows.Add(insertRow); } } return result;}
您可以如何使用此示例:
var test = JoinDataTables(transactionInfo, transactionItems, (row1, row2) => row1.Field<int>("TransactionID") == row2.Field<int>("TransactionID"));
一个警告:这当然没有优化,所以在获得超过20k的行数时要小心。如果您知道一个表将比另一个表大,请尝试将较小的表放在第一个,将较大的表放在第二个表中。
TA贡献1836条经验 获得超3个赞
这是我的代码。不完美,但工作得很好。我希望它对某人有所帮助:
static System.Data.DataTable DtTbl (System.Data.DataTable[] dtToJoin) { System.Data.DataTable dtJoined = new System.Data.DataTable(); foreach (System.Data.DataColumn dc in dtToJoin[0].Columns) dtJoined.Columns.Add(dc.ColumnName); foreach (System.Data.DataTable dt in dtToJoin) foreach (System.Data.DataRow dr1 in dt.Rows) { System.Data.DataRow dr = dtJoined.NewRow(); foreach (System.Data.DataColumn dc in dtToJoin[0].Columns) dr[dc.ColumnName] = dr1[dc.ColumnName]; dtJoined.Rows.Add(dr); } return dtJoined; }
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