萌新求教！数组递归实现过滤指定项求指导！

Question

原数据如下（children层级不定递归实现）vardata={isextend:1,vaL:0,children:[{isextend:1,vaL:1,children:[{isextend:0,vaL:4}]},{isextend:1,vaL:2,children:[]},{isextend:1,vaL:3,children:[]}]}期望变成的类型（过滤isextend=0的项）vardata={isextend:1,vaL:0,children:[{isextend:1,vaL:1,children:[]},{isextend:1,vaL:2,children:[]},{isextend:1,vaL:3,children:[]}]}

Answer 1

记录index在遍历每层数组的最后从后到前删除数组元素----------------上面原答案-------------哎楼主你真好玩我都说了要记录index最后再统一删除你咋就不信呢
                            

Answer 2

functionfilterData(data){
if(data.children){
data.children.forEach((v,index)=>{
if(v.isextend==0){
data.children.splice(index,1)
}
if(v.children){
filterData(v)
}
})
}
returndata;
}
console.log(filterData(data));
有bug