用C来获取终端宽度?我一直在寻找从我的C程序中获得终端宽度的方法。我一直想出的东西是:#include <sys/ioctl.h>#include <stdio.h>int main (void){
struct ttysize ts;
ioctl(0, TIOCGSIZE, &ts);
printf ("lines %d\n", ts.ts_lines);
printf ("columns %d\n", ts.ts_cols);}但每次我试着austin@:~$ gcc test.c -o test
test.c: In function ‘main’:test.c:6: error: storage size of ‘ts’ isn’t known
test.c:7: error: ‘TIOCGSIZE’ undeclared (first use in this function)test.c:7: error: (Each undeclared identifier is reported only once
test.c:7: error: for each function it appears in.)这是最好的方法,还是有更好的方法?如果不是,我怎样才能让它发挥作用?编辑:固定代码是#include <sys/ioctl.h>#include <stdio.h>int main (void){
struct winsize w;
ioctl(0, TIOCGWINSZ, &w);
printf ("lines %d\n", w.ws_row);
printf ("columns %d\n", w.ws_col);
return 0;}
3 回答
慕丝7291255
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#include <stdio.h>#include <stdlib.h>#include <termcap.h>#include <error.h>static char termbuf[2048];int main(void){ char *termtype = getenv("TERM"); if (tgetent(termbuf, termtype) < 0) { error(EXIT_FAILURE, 0, "Could not access the termcap data base.\n"); } int lines = tgetnum("li"); int columns = tgetnum("co"); printf("lines = %d; columns = %d.\n", lines, columns); return 0;}
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info termcap
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