一个简单的jQuery表单验证脚本我使用jQuery制作了一个简单的验证表单。一切正常。问题是我对我的代码不满意。还有其他方法可以用相同的输出结果来编写我的代码吗？$(document).ready(function(){$('.submit').click(function(){
validateForm(); });function validateForm(){
var nameReg = /^[A-Za-z]+$/;
var numberReg = /^[0-9]+$/;
var emailReg = /^([\w-\.]+@([\w-]+\.)+[\w-]{2,4})?$/;
var names = $('#nameInput').val();
var company = $('#companyInput').val();
var email = $('#emailInput').val();
var telephone = $('#telInput').val();
var message = $('#messageInput').val();
var inputVal = new Array(names, company, email, telephone, message);
var inputMessage = new Array("name", "company", "email address", "telephone number", "message");
$('.error').hide();
if(inputVal[0] == ""){
$('#nameLabel').after('<span class="error"> Please enter your ' + inputMessage[0] + '</span>');
}
else if(!nameReg.test(names)){
$('#nameLabel').after('<span class="error"> Letters only</span>');
}
if(inputVal[1] == ""){
$('#companyLabel').after('<span class="error"> Please enter your ' + inputMessage[1] + '</span>');
}
if(inputVal[2] == ""){
$('#emailLabel').after('<span class="error"> Please enter your ' + inputMessage[2] + '</span>');
}
else if(!emailReg.test(email)){
$('#emailLabel').after('<span class="error"> Please enter a valid email address</span>');
}
if(inputVal[3] == ""){
$('#telephoneLabel').after('<span class="error"> Please enter your ' + inputMessage[3] + '</span>');
}
else if(!numberReg.test(telephone)){
$('#telephoneLabel').after('<span class="error"> Numbers only</span>');
}
if(inputVal[4] == ""){
$('#messageLabel').after('<span class="error"> Please enter your ' + inputMessage[4] + '</span>');
} } });
3 回答
斯蒂芬大帝
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