JavaScript 对象数组，如何筛选出有相同key的对象

Question

问题描述：我有下面这样一个数组，数组里面每个对象有三个相同的key：name、age、hair。letnamelist=[{name:'mark',age:15,hair:'long'},{name:'tuwen',age:16,hair:'short'},{name:'xiaoming',age:16,hair:'short'},{name:'lilei',age:15,hair:'short'},{name:'hanmei',age:17,hair:'long'}]筛选条件：数组中age相同的对象分到一个数组里。期望结果：arr_1=[{name:'mark',age:15,hair:'long'},{name:'lilei',age:15,hair:'short'}]arr_2=[{name:'tuwen',age:16,hair:'short'},{name:'xiaoming',age:16,hair:'short'}]arr_3=[{name:'hanmei',age:17,hair:'long'}]

Answer 1

letres=[]
while(nameList.length!==0){
letlist=nameList.shift()
letarr=[list]
for(leti=0;iif(nameList[i].age===list.age){
arr=arr.concat(nameList.splice(i,1))
i--
}
}
res.push(arr)
}
                            

Answer 2

我的思路是先使用map得到所有的age
letone=namelist.map(function(e){
returne.age
})
然后去重
newSet(one)
然后用filter方法，得到你想要的各个数组集合