如何为GSON编写自定义JSON反序列化器?我有一个Java类,用户:public class User{
int id;
String name;
Timestamp updateDate;}我收到一个包含来自webservice的用户对象的JSON列表:[{"id":1,"name":"Jonas","update_date":"1300962900226"},{"id":5,"name":"Test","date_date":"1304782298024"}]我试图编写一个自定义反序列化器:@Overridepublic User deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
return new User(
json.getAsJsonPrimitive().getAsInt(),
json.getAsString(),
json.getAsInt(),
(Timestamp)context.deserialize(json.getAsJsonPrimitive(),
Timestamp.class));}但我的反序列化器不起作用。如何为GSON编写自定义JSON反序列化程序?
3 回答
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@Overridepublic User deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
JsonObject jobject = json.getAsJsonObject();
return new User(
jobject.get("id").getAsInt(),
jobject.get("name").getAsString(),
new Timestamp(jobject.get("update_date").getAsLong()));}
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// output:// [User: id=1, name=Jonas, updateDate=2011-03-24 03:35:00.226]// [User: id=5, name=Test, updateDate=2011-05-07 08:31:38.024]
// using java.sql.Timestamppublic class Foo{
static String jsonInput =
"[" +
"{\"id\":1,\"name\":\"Jonas\",\"update_date\":\"1300962900226\"}," +
"{\"id\":5,\"name\":\"Test\",\"update_date\":\"1304782298024\"}" +
"]";
public static void main(String[] args)
{
GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.setFieldNamingPolicy(FieldNamingPolicy.LOWER_CASE_WITH_UNDERSCORES);
gsonBuilder.registerTypeAdapter(Timestamp.class, new TimestampDeserializer());
Gson gson = gsonBuilder.create();
User[] users = gson.fromJson(jsonInput, User[].class);
for (User user : users)
{
System.out.println(user);
}
}}class User{
int id;
String name;
Timestamp updateDate;
@Override
public String toString()
{
return String.format(
"[User: id=%1$d, name=%2$s, updateDate=%3$s]",
id, name, updateDate);
}}class TimestampDeserializer implements JsonDeserializer<Timestamp>{
@Override
public Timestamp deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context)
throws JsonParseException
{
long time = Long.parseLong(json.getAsString());
return new Timestamp(time);
}}添加回答
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