3 回答
TA贡献1829条经验 获得超4个赞
SELECT @row := @row + 1 as row, t.*FROM some_table t, (SELECT @row := 0) r
@row
TA贡献1852条经验 获得超7个赞
以下内容将返回1.10000,并且不会太慢
SELECT @row := @row + 1 AS row FROM
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t4,
(SELECT @row:=0) numbers;
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