警告：mysqli_query()至少需要2个参数，其中1个给定。什么？我创建了一个PHP页面，该页面应该从数据库中选择两个名称并显示它们。它只是说：Warning: mysqli_query() expects at least 2 parameters, 1 given in /home/tdoylex1/public_html/dorkhub/index.php on line 4Warning: mysqli_query() expects at least 2 parameters, 1 given in /home/tdoylex1/public_html/dorkhub/index.php on line 8我的代码是：<?php mysqli_connect(localhost,tdoylex1_dork,dorkk,tdoylex1_dork);$name1 = mysqli_query("SELECT name1 FROM users
ORDER BY RAND()
LIMIT 1");$name2 = mysqli_query("SELECT name FROM users
ORDER BY RAND()
LIMIT 1");?><title>DorkHub. The online name-rating website.</title><link rel="stylesheet" type="text/css" href="style.css"><body bgcolor='EAEAEA'><center><div id='TITLE'>
<h2>DorkHub. The online name-rating website.</h2></div>
<p>
<br>
<h3><?php echo $name1; ?></h3><h4> against </h4><h3><?php echo $name1; ?></h3>
<br><br>
<h2 style='font-family:Arial, Helvetica, sans-serif;'>Who's sounds the dorkiest?</h2>
<br><br>
<div id='vote'>
<h3 id='done' style='margin-right: 10px'>VOTE FOR FIRST</h3><h3 id='done'>VOTE FOR LAST</h3>
2 回答
慕娘9325324
TA贡献1783条经验 获得超4个赞
mysqli_querymysqli_connect
$name1 = mysqli_connect(localhost,tdoylex1_dork,dorkk,tdoylex1_dork);$name2 = mysqli_query($name1,"SELECT name FROM users ORDER BY RAND() LIMIT 1");
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