请各位大佬指点！js 根据日期 对数组重新分组各位有什么建议？

Question

原数据：vardata=[{"name":"小明","age":"4","birthday":"5-1"},{"name":"小黄","age":"4","birthday":"5-1"},{"name":"小红","age":"4","birthday":"5-3"},]希望整理后得到：varnewArr=[{"birthday":"5-1","detailList":"[{'name':'小明','age':'4'},{'name':'小黄','age':'4'}]"},{"birthday":"5-3","detailList":"[{'name':'小红','age':'4'}]"}];我的思路；data数组第0项直接push（birthday+detailList）整个到新数组newArr，但从第1项就要开始去newArr比较birthday，如果birthday相同，就只用push（detailList），如果不同就push{birthday+detailList}遇到问题：重复打印了一些数据我的代码：`vardata=[{"name":"小明","age":"4","birthday":"5-1"},{"name":"小黄","age":"4","birthday":"5-1"},{"name":"小红","age":"4","birthday":"5-3"},]//[希望得到]//varnewArr=[//{//"birthday":"5-1",//"detailList":"[{'name':'小明','age':'4'},{'name':'小黄','age':'4'}]"//},//{//"birthday":"5-3",//"detailList":"[{'name':'小红','age':'4'}]"//}//];vararr=[];//存放新数组for(vari=0;i

Answer 1

下面这段代码修改如下：
//第1个就要开始找新数组arr相同的日期
else{
varindex=-1;//通过for循环查找index
for(vark=0;kif(resBirthday==arr[k].birthday){
index=k;
break;
}
}
if(index===-1){//没有找到
arr.push(valItem);
}else{//找到了
arr[k].detailList.push(valDetailList);
}
}