在线等，挺急的！根据id值的不同做筛选？

Question

就是拿一组ID跟另一个数组做比较如果有相同得放到相同得新数组里有不相同的放到不相同数组中

Answer 1

[...arr1,...arr2].reduce((result,v)=>{
letindex=result.diff.indexOf(v)
if(index!==-1){
result.same.push(result.diff.splice(index,1)[0]);
}else{
result.diff.push(v);
}
returnresult;
},{same:[],diff:[]})
                            

Answer 2

consta=[1,2,3,4];
constb=[2,3,5,6];
functionfilterArr(arr1,arr2,type){
letdiffArr=[];
letsameArr=[];
sameArr=arr1.filter(v=>{
returnarr2.some(a=>{
returnv==a
})
})
letmergeArr=[...arr1,...arr2];
diffArr=mergeArr.filter(v=>{
return!sameArr.includes(v)
})
if(type=='same'){
returnsameArr
}else{
returndiffArr
}
}
console.log(filterArr(a,b,'same'))//[2,3]
console.log(filterArr(a,b,'diff'))//[1,4,5,6]