python flask中怎样获取form的id或name属性。注意是form的属性不是用户的输入值

Question

比如html中：<form method="post" enctype=multipart/form-data id="0" ><input type=file name=file ><input type=submit value=上传></form>在后端的python中怎么能获取到这个form的id？想判断if request.method == 'POST' 且 form的id=0时再进行下一步。

Answer 1

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<form action="upload" method="post" enctype="multipart/form-data">     <input type="hidden" style="visibility: hidden;" name="formname" value="name0" />     <input type="hidden" style="visibility: hidden;" name="formid" value="0" />     <input type="file" name="file" /><br />     <input type="submit" value="Upload" /> </form>

 

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@app.route('/upload', methods=['GET', 'POST']) def upload():     if request.method == 'GET':         return render_template('upload.html')     elif request.method == 'POST':         f = request.files['file']         print request.form['formname'],request.form['formid']         fname = secure_filename(f.filename)         f.save(os.path.join(UPLOAD_FOLDER, fname))         return '上传成功'