php if判断 如何使用条件表达式

Question

$price=123;$price1=124;$symbol=">";//可能是

Answer 1

functioncompare($a,$b,callable$compare){
return$compare($a,$b);
}
functionmore($a,$b){
return$a>$b;
}
functionless($a,$b){
return$a<$b;
}
functionequal($a,$b){
return$a==$b;
}
var_dump(compare(123,124,'more'));
var_dump(compare(123,124,'less'));
var_dump(compare(123,124,'equal'));
var_dump(compare(123,123,'equal'));
简化版
functioncompare($a,$b,$symbol){
$compare=[
'>'=>function($a,$b){return$a>$b;},
'<'=>function($a,$b){return$a<$b;},
'='=>function($a,$b){return$a==$b;}
];
return$compare[$symbol]($a,$b);
}
var_dump(compare(123,124,'>'));
var_dump(compare(123,124,'<'));
var_dump(compare(123,124,'='));
var_dump(compare(123,123,'='));
                            

Answer 2

肯定是不可以的建议写一个方法，传递这三个参数，然后内部判断
functionaaa($symbol,$prcie,$price1){
if($symbol=='='){
if($price1==$price){
returntrue
}else{
returnfalse
}
}elseif($symbol=='>'){
if($price1>$price){
returntrue
}else{
returnfalse
}
}elseif($symbol=='<'){
if($price1<$price){
returntrue
}else{
returnfalse
}
}
}