python 简单计数器的实现

Question

各位大佬好，我想要写一个计数器，每次一个循环后，计数器数量加一，但不知道怎么实现。麻烦各位赐教defcount_turn(turn=0):ifturn==0:turn+=1elifturn>=1:turn+=1returnturndefadd_turn(turn):turn+=1returnturndefleave_stay():print("="*50)reply=input("Doyouwanttoquitthegameorcontinueplaying?""\n'q'forquit,'c'forcontinue")print("")returnreplydefexecute(reply,):ifreply=='q':signal=Falsereturnsignalelifreply=='c':main()else:leave_stay()defmain(turn=0):turn=count_turn(turn)print("first:",turn)signal=Trueifsignal:turn=count_turn(turn)turn=add_turn(turn)print("hereistheturn:",turn)reply=leave_stay()execute(reply)main()

Answer 1

classCounter(object):
def__init__(self,start=0):
self.num=start
defcount(self):
self.num+=1
returnself.num
调用如下：
>>>c=Counter()
>>>c.count()
1
>>>c.count()
2
                            

Answer 2

defexecute(reply,):
whilereplynotin'qc':
reply=leave_stay()
returnTrueifreply=='c'elseFalse
defmain(turn=0):
turn=count_turn(turn)
print("first:",turn)
signal=True
whilesignal:
turn=count_turn(turn)
print("hereistheturn:",turn)
reply=leave_stay()
signal=execute(reply)
main()