怎么过滤出一组号码中的顺子号码？

Question

比如有1,2,5,6,7,11,14这组号码，怎么过滤出[1,2]和[5,6,7]这两组号码？求指点

Answer 1

这种逻辑？
vararr=[1,2,5,6,7,11,14];
varlen=arr.length,
before=arr[0],
i=1,
res=[],
result=[],
current;
for(;icurrent=arr[i];
if(current-before===1){
if(res.length===0)
res.push(before);
res.push(current);
}else{
if(res.length){
result.push(res);
}
res=[];
}
before=current;
}
if(res.length){
result.push(res);
}
console.log(result);
                            

Answer 2

这样行吗？
functionsubsequence(arr){
if(!arr||arr.length<2)return[];
letresult=[],
curr=arr[0],
subArr=[curr];
for(leti=1;iif(arr[i]===curr+1){
subArr.push(arr[i]);
curr=arr[i];
}else{
if(subArr.length>1){
result.push(subArr);
}
curr=arr[i];
subArr=[curr];
}
}
if(subArr.length>1){
result.push(subArr);
}
returnresult;
}
//test
console.log(subsequence([]));
console.log(subsequence([0]));
console.log(subsequence([1,2,5,6,7,11,14]));
console.log(subsequence([1,2,3,4,7,8,9,11,23,45,56,66,67]));
console.log(subsequence([9,8,7,7,8,9,0]));