寻找更实用的“功能”方式......我有一个产品的对象看起来像这样(注意重复skuid的)"products": [
{
"skuid": "B1418",
"name": "Test Product 1",
"price": 7,
"lastOrderedDate": 20181114,
"quantity": 2
},{
"skuid": "B3446",
"name": "Test Product 2",
"price": 6,
"lastOrderedDate": 20190114,
"quantity": 2
},{
"skuid": "B1418",
"name": "Test Product 1",
"price": 7,
"lastOrderedDate": 20180516,
"quantity": 5
},{
"skuid": "B3446",
"name": "Test Product 2",
"price": 6,
"lastOrderedDate": 20180411,
"quantity": 11
}]我想创建一个新的数组,每个不同的单个对象,skuid但SUMS所有的quantity值,并保留最新的lastOrderedDate。最终结果如下:"products": [
{
"skuid": "B1418",
"name": "Test Product 1",
"price": 7,
"lastOrderedDate": 20181114,
"quantity": 7
},{
"skuid": "B3446",
"name": "Test Product 2",
"price": 6,
"lastOrderedDate": 20190114,
"quantity": 13
}]我可以用一堆forEach和if来做,但我想学习一种更简洁的方法来做到这一点。或许有一种,那么reduce?
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