java中出现一个嵌套问题

Question

import java.util.Random;import java.util.Scanner;public class Chenwei_GuessNumber{static int m=8;/*** @param args*/public static void main(String[] args) {     // TODO Auto-generated method stub     Scanner input = new Scanner(System.in);     Random ran = new Random();     int number = ran.nextInt(100)+1; // 产生随机数     for (;;)     {         System.out.println("1.开始猜数");         System.out.println("2.游戏参数设置");         System.out.println("9.退出");         Scanner sc=new Scanner(System.in);         String choo =sc.next();         if (!choo.equals("1")&&!choo.equals("2")&&!choo.equals("9"))         {             System.out.println("属于非法输入");         }         else         {             if (choo.equals("1"))                 {             int guess;      // 用户猜的数字             int count = 0;  // 猜测次数             System.out.println("有一个0到100之间的整数，你猜是什么？");             do {             guess = input.nextInt();             if (number < guess) {             System.out.println("大了，再猜");          count++;             } else if (number > guess) {             System.out.println("小了，再猜");             count++;             } else {                     count++;                     break;                 }                        if (guess > count){                     System.out.println("次数超过");                     break;                 }             else if(guess <= count) {                     {break;}             }eclipse中Syntax error, insert "while ( Expression ) ;" to complete DoStatementSyntax error on token "}", { expected after this token删除了break的分号底下的count报错。pss：现在是这样的

Answer 1

  {break;}
        }
这里多了一个后括号

 while (true);
 这里多了一个分号

Answer 2

while(true) 后面的分号；是正解呀