实现一个class Lazing 函数，输出如下该怎么写?

Question

Lazing('Garry')//输出'helloGarray'Lazing('Garry').sleep(10).eat('rice')//输出'helloGarray'//等待10秒...//输出'eatingrice'Lazing('Garry').eat('rice').eat('bread')//输出'eatingrice'//输出'eatingbread'Lazing('Garry').sleepFirst(5).eat('rice')//等待5秒...//输出'helloGarray'//输出'eatingrice'难点是定时器该怎么处理？如果sleepFirst定时器是后置的怎么来实现？Lazing('Garry').eat('rice').sleepFirst(5)//等待5秒...//输出'helloGarray'//输出'eatingrice'

Answer 1

总体思路就是构造一个任务队列
classLazing{
constructor(item=''){
this.queue=[{
key:'init',
val(){
console.log('hello'+item)
}
}]
}
eat(item){
this.queue.push({
key:'eat',
val(){
console.log('eating'+item)
}
})
returnthis
}
sleep(time){
this.queue.push({
key:'sleep',
val:time*1000
})
returnthis
}
sleepFirst(time){
this.queue.unshift({
key:'sleep',
val:time*1000
})
returnthis
}
exec(){
for(leti=0;iletkey=this.queue[i]['key']
letval=this.queue[i]['val']
if(key==='sleep'){
this.queue.shift()
setTimeout(this.exec.bind(this),val)
break
}else{
val()
this.queue.shift()
i--
}
}
}
}
不过调用方式稍微不一样些，但能达到效果
newLazing('Garry').exec()
newLazing('Garry').sleep(3).eat('rice').exec()
newLazing('Garry').eat('rice').eat('bread').exec()
newLazing('Garry').sleepFirst(3).eat('rice').exec()
newLazing('Garry').eat('rice').sleepFirst(3).exec()