我有一个方法,每次都必须传入一个固定的对象paint,因为这个函数会被频繁调用,所以我不能在内联函数中创建对象。inlinefunCanvas.drawPoint(point:PointF,paint:Paint){drawPoint(point.x,point.y,paint)}但是我很多地方都会调用这个方法。//(Canvas.apply(..,..))drawPoint(pointA,pointPaint)drawPoint(pointB,pointPaint)drawPoint(pointC,pointPaint)drawPoint(pointD,pointPaint)可以看到每次都会传入一个pointPaint对象。所以我在想有没有类似这样一个功能//(Canvas.apply(..,..))bind(pointPaint)drawPoint(pointA)drawPoint(pointB)drawPoint(pointC)drawPoint(pointD)
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四季花海
TA贡献1811条经验 获得超5个赞
完美符合你要求的方式肯定是没有的,因为bind函数不可能改变另一个函数内部的局部变量。折中的方式也有很多,比如定义一个包级属性:vardrawPaint:Paint?=null然后原来的函数改为:inlinefunCanvas.drawPoint(point:PointF,paint:Paint){paint?.let{drawPoint(point.x,point.y,it)}}方便使用还可以再定义一个函数来确保drawPaint能被准确的赋值和释放:funbindPaint(paint:Paint,action:()->Unit){drawPaint=paintaction()drawPaint=null}这样使用时就是://Canvas().apply{bindPaint(somePaint){drawPoint(x,y)}还有一种方式是定义一个包装类,并在其中定义一个包含带接收者Lambda表达式的参数的函数(接收者为Canvas),然后将扩展函数定义到这个类中:classPointPainter(privatevalpaint:Paint){funCanvas.drawPoint(rect:RectF){drawPoint(rect.x,rect.y,paint)}}然后定义含有接收者为这个包装对象Lambda参数的函数:funbindPointPainter(paint:Paint,drawAction:PointPainter.()->Unit){PointPainter(paint).drawAction()}这样用时更方便一些://incanvas.applyblockbindPointPainter(somePaint){drawPoint(rect1)drawPoint(rect2)//...}
MYYA
TA贡献1868条经验 获得超4个赞
funtest(){Canvas().bindPaintDrawPoints(Paint())(arrayOf(PointF(1f,2f),PointF(2f,2f),PointF(3f,2f),PointF(4f,2f)))}funCanvas.bindPaintDrawPoints(paint:Paint):(Array)->Unit{ return{drawPoints(paint,it)}}funCanvas.drawPoints(paint:Paint,points:Array){ for(pinpoints){this.drawPoint(p.x,p.y,paint)}}
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