数组[a,b,c,d]如何递归成a:{b:{c:{d:"test"}}}

Question

vartest="a.b.c.d"如何递归成a:{b:{c:{d:"test"}}}

Answer 1

循环算法：
vartest="a.b.c.d";
varret="test";
vararr=test.split(".");
do{
varkey=arr.pop();
varobj={};
obj[key]=ret;
ret=obj;
}while(arr.length);
console.log(ret);
递归算法：
vartest="a.b.c.d";
vararr=test.split(".");
vari=arr.length;
varret=(functionmerge(val){
if(i--){
varobj={};
obj[arr[i]]=val;
val=obj;
returnmerge(val);
}elsereturnval;
})("test");
console.log(ret);
                            

Answer 2

vartest="a.b.c.d"
constrecur=(objkey,test)=>(f=arr=>arr.length?{[arr.shift()]:f(arr)}:test)(objkey.split('.'))
console.log(recur(test,'test'))