async/await 实现 promise 红 绿 蓝灯问题

Question

前言之前网上有一个promise实现红绿蓝灯交替亮的问题，我再次描述一下问题。题目：红灯三秒亮一次，绿灯一秒亮一次，黄灯2秒亮一次；如何让三个灯不断交替重复亮灯？（用Promse实现）functionred(){console.log('red');}functiongreen(){console.log('green');}functionyellow(){console.log('yellow');}然后我最近学习asyncawait的时候来试着实现这个功能。但是我觉得我写的代码不太好，但是又不知道怎么优化，在此贴出希望有人给点建议来优化一下感谢ing！functionred(){console.log('red');}functiongreen(){console.log('green');}functionblue(){console.log('blue');}functionmiddle(cb,time,time1){returnnewPromise((resolve,reject)=>{setTimeout(()=>{cb();resolve(time1);},time);});}asyncfunctionsetp1(){constrTime=awaitmiddle(red,3000,1000);constgTime=awaitmiddle(green,rTime,2000);constbTime=awaitmiddle(blue,gTime);setp1();}setp1();

Answer 1

functionred(){
console.log('red');
}
functiongreen(){
console.log('green');
}
functionblue(){
console.log('blue');
}
functionwait(time){
returnnewPromise((resolve,reject)=>{
setTimeout(resolve,time)
})
}
asyncfunctionmarquee(){
awaitwait(3000)
red()
awaitwait(1000)
green()
awaitwait(2000)
blue()
marquee()
}
marquee()
                            

Answer 2

两个参数就够啦
functionred(){
console.log('red');
}
functiongreen(){
console.log('green');
}
functionblue(){
console.log('blue');
}
functionmiddle(cb,time){
returnnewPromise((resolve,reject)=>{
setTimeout(()=>{
cb();
resolve();
},time*1000);
});
}
asyncfunctionsetp1(){
constrTime=awaitmiddle(red,3);
constgTime=awaitmiddle(green,1);
constbTime=awaitmiddle(blue,2);
setp1();
}
setp1();