从json对象中获得正确的输出值

Question

代码如下：JSONObject jChild=new JSONObject();          JSONObject jParent=new JSONObject();             for (Product p : boxAdapter.getBox()) {               if (p.checked){                 try {                     jChild.put("uid", p.uid);                 list.add(String.valueOf(jChild));                     //list.add(String.valueOf(jParent));                 } catch (JSONException e) {                     e.printStackTrace();                 }               }             }             jParent.put("users", list);           // Toast.makeText(this, ""+jParent, Toast.LENGTH_LONG).show();             Log.v("TakeAttendance","JSONpARENT "+String.valueOf(jParent));输出：{"users":"[{\"uid\":\"4\"}, {\"uid\":\"5\"}, {\"uid\":\"6\"}]"}我所需要的是：{users: [     {     name: "acx",     uid: "2"     },     {     name: "test",     uid: "6"     },     {     name: "ccc",     uid: "11"     }     ]     }

Answer 1

private void jsonTest() {
try {
JSONObject json = new JSONObject();
JSONArray jsonArr = new JSONArray();
for (int i = 0; i < 3; i++) {
JSONObject arrObj = new JSONObject();
arrObj.put("name", "test");
arrObj.put("uid", i);
jsonArr.put(arrObj);
}
json.put("users", jsonArr);

        Log.e("LH", "json==" + json);
    } catch (JSONException e) {
        e.printStackTrace();
    }
}

Answer 2

只需要把上面那哥们的
Log.e("LH", "json==" + json);改成 Log.e("LH", "json==" + json.toString());