python字典如何计算键值对的总数

Question

{'a':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),'b':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),'c':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),'d':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),'e':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),'f':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),'g':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456')}如上，键值对有70，使用len()方法只能得出7，求在最好不用FOR循环的情况用dict对象最优的自带方法使结果为70（如果有的话）

Answer 1

追求性能能的情况下，列表推导性能最高，循环次之，map最差
所以写法应该是用列表推导更合适
sum([len(_)for_ind.values()])
                            

Answer 2

那你这是不算是计算键值对的数量啊...而是计算每个值的length之和，所以没有办法使用dict对象内置的东东来解决
目前我想到的方法就是
sum(map(lambdax:len(x)ifhasattr(x,"__len__")else1,v)
//v是你的dict
抛砖引玉吧