社区求助 js 数组组合成需要的新数组

Question

vararr=[{"areaName":"北欧","countryName":"阿布哈兹","packageName":"测试1","packagePrice":"1.0","mark":0},{"areaName":"西欧","countryName":"德国","packageName":"测试3","packagePrice":"14.0","mark":1},{"areaName":"北欧","countryName":"丹麦","packageName":"测试2","packagePrice":"14.0","mark":0}]需要的新数组格式为vararr2=[{"areaName":"北欧","mark":0,"list":[{"countryName":"阿布哈兹","packageName":"测试1","packagePrice":"1.0",},{"countryName":"丹麦","packageName":"测试2","packagePrice":"14.0",}]},{"areaName":"西欧","mark":1,"list":[{"countryName":"德国","packageName":"测试3","packagePrice":"14.0",}]}]

Answer 1

functiontransform(arr){
constobj={}
arr.forEach(item=>{
const{mark,areaName,...rest}=item
if(!obj[item.mark]){
obj[mark]={
mark,
areaName,
list:[rest],
}
}else{
obj[mark].list.push(rest)
}
})
returnObject.values(obj)
}
                            

Answer 2

写了一个方法，可能不是最简单的实现方法，仅供参考：
letarr=[];//这里是你上面的数据
lettemp_obj={};
arr.map(item=>{
letbuff_property="mark"+item.mark;
if(temp_obj[buff_property]){
temp_obj[buff_property].list.push({
"countryName":item.countryName,
"packageName":item.packageName,
"packagePrice":item.packagePrice
})
}else{
temp_obj[buff_property]={
"areaName":item.areaName,
"mark":item.mark,
"list":[
{
"countryName":item.countryName,
"packageName":item.packageName,
"packagePrice":item.packagePrice
}
]
}
}
returnitem;
})
letarr2=Object.values(temp_obj);
temp_obj=null;//使用完成，释放内存
console.log(arr2);