js中为什么字符串中加了\n匹配就一直失败

Question

这样没结果vars='hi\nabc454def';console.log(/h.+(\d+)def/g.exec(s));这样是有结果的vars='hiabc454def';console.log(/h.+(\d+)def/g.exec(s));

Answer 1

vars='hi\nabc454def';
console.log(/h[\s\S]+(\d+)def/g.exec(s));//["hi↵abc454def","4",index:0,input:"hi↵abc454def"]
console.log(/h[\w\W]+(\d+)def/g.exec(s));//["hi↵abc454def","4",index:0,input:"hi↵abc454def"]