lua语言一个数组的问题。

Question

function minzhi()local days={"1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","j","k","l","q","w","e","r","t","y","u","i","o","p","z","x","c","v","b","n","m"}endprint (minzhi())如何让函数每次运行，从第一个数组开起输出，一直到最后一个，又从第一个输出，这样循环显示

Answer 1

用 closure 最简单，比如下面的代码，每次调用 minzhi() 都会打印 days 里的元素。

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function newMinzhi()     local days={"1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","j","k","l","q","w",         "e","r","t","y","u","i","o","p","z","x","c","v","b","n","m"}     local idx = 1     return function ()         if idx > #days then             idx = 1         end         print(days[idx])         idx = idx + 1     end end   minzhi = newMinzhi() minzhi()   -- 打印 1 minzhi()   -- 打印 2 minzhi()   -- 打印 3 ................

 

Answer 2

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-- 之前的版本直接把内容打印出来了，现在的版本改成返回 days 中的值。   function newMinzhi()     local days= {"中", "国"}     local idx = 1     return function ()         if idx > #days then             idx = 1         end         local ret = days[idx]         idx = idx + 1         return ret     end end minzhi = newMinzhi() print(minzhi()) print(minzhi())