java如何消除繁琐的if else 语句？

Question

求助：一堆的ifelse嵌套privateMapversionCheck(MapmapParam){Mapmsg=newHashMap();if(!"".equals(PMSUtil.isNull(mapParam.get("IS_INTERNET")))){StringcheckVersion=SystemGlobals.getProperty("IS_CHECK");if("1".equals(checkVersion)){Stringversions=SystemGlobals.getProperty("VERSION");Stringversion=PMSUtil.isNull(mapParam.get("VERSION"));StringtaxRegisterNo=PMSUtil.isNull(mapParam.get(""));StringwhiteList=SystemGlobals.getProperty("NO_CHECK_TAX_REGISTER_NO");if((","+whiteList+",").indexOf((","+taxRegisterNo+","))==-1){if((","+versions+",").indexOf(","+version+",")==-1){//找不到msg.put("RESULT","0001");msg.put("MSG","FAILD");}else{msg.put("RESULT",""0000"");}}else{msg.put("RESULT",""0000"");}}else{msg.put("RESULT",""0000"");}}else{msg.put("RESULT",""0000"");}returnmsg;}

Answer 1

1.整体可简化为：
if(){
if(){
if(){
if(){
msg.put("RESULT","0001");
msg.put("MSG","FAILD");
returnmsg;
}
}
}
}
msg.put("RESULT","0000");
returnmsg;
2.str.indexOf(s)==-1可简化为!str.contains(s)
3.使用2之后，最里层的两个if语句：
if(c1){
if(c2){
...
}
}
可以写成：
if(c1&&c2){
...
}