PHP计算出两个年份的相差的月份，注意我只要月份，比如 "2013-07-03" "2014-03-12"

Question

PHP计算出两个年份的相差的月份，注意我只要月份，比如"2013-07-03""2014-03-12"，他们相差的8个月，那么你的函数中必须返回8，注意代码冗余

Answer 1

上一个回答没考虑年份差（不过题主强调了只需要月份），这里补上@2014-03-2710:06:25：
$time_begin=strtotime("2012-07-03");
$time_end=strtotime("2014-03-12");
$time_differ=$time_end-$time_begin;
$year_differ=date('Y',$time_differ);
$month_differ=date('m',$time_differ);
$result=12*intval($year_differ-1970)+intval($month_differ)-1;
$time_begin=strtotime("2013-07-03");
$time_end=strtotime("2014-03-12");
$time_differ=$time_end-$time_begin;
$month_differ=date('m',$time_differ);
$result=intval($month_differ)-1;
亲测可行。
                            

Answer 2

$d1=newDateTime('2013-07-03');
$d2=newDateTime('2014-03-12');
$diff=$d2->diff($d1);
echo($diff->y*12)+$diff->m;