js 函数式编程问题

Question

在codewars上看到的一道函数式编程题要求写出0～9十个函数和加减乘除四个函数，最终实现以下功能seven(times(five()));//mustreturn35four(plus(nine()));//mustreturn13eight(minus(three()));//mustreturn5six(dividedBy(two()));//mustreturn3有点绕晕了，麻烦大能解惑下，不胜感激。

Answer 1

大概这个意思吧.
functionone(fun)
{
if(fun)returnfun(1);
return1;
}
functiontwo(fun)
{
if(fun)returnfun(2);
return2;
}
functionplus(num)
{
returnfunction(a){returna+num;}
}
one(plus(two()));
                            

Answer 2

对js不熟，应该是这样：
functionpartial_op_with_oper2(op,oper2){
returnfunction(oper1){
returnop(oper1,oper2);
};
}
functionmake_operand(value){
returnfunction(oper2){
if(oper2){
returnoper2(value);
}else{
returnvalue;
}
};
}
//"Operators"
vartimes=function(b){
varop=function(a,b){returna*b;};
returnpartial_op_with_oper2(op,b);
};
varplus=function(b){
varop=function(a,b){returna+b;};
returnpartial_op_with_oper2(op,b);
};
//"Operands"
varzero=make_operand(0);
varone=make_operand(1);
vartwo=make_operand(2);
varthree=make_operand(3);
varfour=make_operand(4);
varfive=make_operand(5);
varsix=make_operand(6);
varseven=make_operand(7);
vareight=make_operand(8);
varnine=make_operand(9);
跟@brayden的一个意思