数组合并方法

Question

var arr1=['name', 'age', 'home']var arr2=[['a', 'b', 'c', 'd', 'e'], [1,2,3,4,5], ['one', 'two', 'three', 'four', 'five']]var arr3=[{'name':'a','age':1, 'home':'one'}, {'name':'b','age':2, 'home':'two'}, {'name':'c','age':3, 'home':'three'}, {'name':'d','age':4, 'home':'four'}, {'name':'e','age':5, 'home':'five'}];已知数组1和2，求写一种方法得到数组3的形式

Answer 1

function trans (names, arr) {

  let result = []

  for (let i = 0, len = arr[0].length; i < len; i++) {

    let obj = {}

    names.forEach((name, index) => {

      obj[name] = arr[index][i]

    })

    result.push(obj)

  }

  return result

}

var arr1=['name', 'age', 'home']

var arr2=[['a', 'b', 'c', 'd', 'e'], [1,2,3,4,5], ['one', 'two', 'three', 'four', 'five']]

trans(arr1, arr2)

Answer 2

var arr1=['name', 'age', 'home']

var arr2=[['a', 'b', 'c', 'd', 'e'], [1,2,3,4,5], ['one', 'two', 'three', 'four', 'five']]

arr2[0].map((item, index) => {

return arr1.reduce((a, b, i) => (a[b] = arr2[i][index], a), {})

})