多个对象怎么组合成一个数组对象

Question

{"date":{"0":"20180201","1":"20180202","2":"20180205"},"lines":{"0":3.3,"1":10.4,"2":79.721},"count":{"0":5,"1":21,"2":13},"counts":{"0":5,"1":26,"2":39},"limit":{"0":3.3,"1":13.7,"2":93.421}}// 最后我想变成下面这种格式，怎么弄呢let values = [{date: '20180201', lines: 3.3,count: 5,countS: 5,limit: 3.3},{date: '20180202', lines: 10.4,count: 21,countS: 26,limit: 13.7}...];

Answer 1

const obj = {

  "date": {"0": "20180201", "1": "20180202", "2": "20180205"},

  "lines": {"0": 3.3, "1": 10.4, "2": 79.721},

  "count": {"0": 5, "1": 21, "2": 13},

  "counts": {"0": 5, "1": 26, "2": 39},

  "limit": {"0": 3.3, "1": 13.7, "2": 93.421}

};

const keys = Object.keys(obj);

const lens = Object.keys(obj[keys[0]]);

let arrays = []

for (const len of lens) {

  let o = {};

  for (const key of keys) {

    o[key] = obj[key][len];

  }

  arrays.push(o);

}

console.log(arrays);

结果：

[ { date: '20180201', lines: 3.3, count: 5, counts: 5, limit: 3.3 },

  { date: '20180202',

    lines: 10.4,

    count: 21,

    counts: 26,

    limit: 13.7 },

  { date: '20180205',

    lines: 79.721,

    count: 13,

    counts: 39,

    limit: 93.421 } ]

新需求：

const obj = {

  "v_date": {"0": "20180201", "1": "20180202", "2": "20180205", "3": "20180206", "4": "20180207", "5": "20180208"},

  "type": {"0": "现券交易", "1": "现券交易", "2": "质押式回购", "3": "质押式回购", "4": "质押式回购", "5": "现券交易"},

  "amt": {"0": 3.3, "1": 10.4, "2": 79.721, "3": 68.363, "4": 25.674, "5": 12.1},

  "num": {"0": 5, "1": 21, "2": 13, "3": 21, "4": 18, "5": 32},

  "sum_num": {"0": 5, "1": 26, "2": 13, "3": 34, "4": 52, "5": 58},

  "sum_amt": {"0": 3.3, "1": 13.7, "2": 79.721, "3": 148.084, "4": 173.758, "5": 25.8}

};

const keys = Object.keys(obj);

const lens = Object.keys(obj.type);

let types = {};

for (const t of lens) {

  if(!types[obj.type[t]]) {

    types[obj.type[t]] = [];

  }

  let o = {};

  for (const key of keys) {

    if (key !== 'type') {

      o[key] = obj[key][t]

    }

  }

  types[obj.type[t]].push(o);

}

console.log(types)

结果：

{ '现券交易': 

   [ { v_date: '20180201', amt: 3.3, num: 5, sum_num: 5, sum_amt: 3.3 },

     { v_date: '20180202',

       amt: 10.4,

       num: 21,

       sum_num: 26,

       sum_amt: 13.7 },

     { v_date: '20180208',

       amt: 12.1,

       num: 32,

       sum_num: 58,

       sum_amt: 25.8 } ],

  '质押式回购': 

   [ { v_date: '20180205',

       amt: 79.721,

       num: 13,

       sum_num: 13,

       sum_amt: 79.721 },

     { v_date: '20180206',

       amt: 68.363,

       num: 21,

       sum_num: 34,

       sum_amt: 148.084 },

     { v_date: '20180207',

       amt: 25.674,

       num: 18,

       sum_num: 52,

       sum_amt: 173.758 } ] }

当你执行console.log(Object.values(types))的时候，你会发现更多的惊喜

Answer 2

let arr = []

for(let key in obj) {

    arr.push(obj[key])

}

console.log(arr)

Answer 3

source为你最开始那个对象

for(var i =0,len=3;i<len;i++){

    values[i].date=source['date'][i];

    values[i].lines=source['lines'][i];

    ...

}

Answer 4

const oData = {

"date":{"0":"20180201","1":"20180202","2":"20180205"},

"lines":{"0":3.3,"1":10.4,"2":79.721},

"count":{"0":5,"1":21,"2":13},

"counts":{"0":5,"1":26,"2":39},

"limit":{"0":3.3,"1":13.7,"2":93.421}

},

fnData = function(o, l, a = [], i = 0) {

 for (let k in oData) {

   if (!a[i]) a[i] = {};

   a[i][k] = o[k][i];

 }

 return ++i < l && fnData(o, l, a, i) || a;

};

alert(JSON.stringify(fnData(oData, 3)));