PHP调用webservice,返回字符串但取不到返回值

Question

PHP调用webservice，但取不到返回值，在网页上直接获取是可以拿到返回值的。 获取返回值的方法如下： ini_set("soap.wsdl_cache_enabled",0); function getSoapData($cardNo){ echo '##########################,'; echo $cardNo; try { // 示例webservice地址. $client = new SoapClient ( "http://soap.org/wsdl?", array ( 'encoding' => 'UTF-8' ) ); $strinfo = $client-> GetOpenID( array ( 'CardNo'=>$cardNo ) ); echo ',##########################'.$client->GetOpenID($cardNo); } catch ( Exception $e ) { echo 'ERR\n\n\n'; Think\Log::record ( $e, 'ERR' ); } return $strinfo; } 网页上的返回值是： <SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:s="http://www.w3.org/2001/XMLSchema"> <SOAP-ENV:Body> <GetOpenIDResponse xmlns="http://www.xxxxxxxx.cn"> <GetOpenIDResult>fdlsakfjsdlafsdkllfk02943ielkdsjfalsdk12878</GetOpenIDResult> </GetOpenIDResponse> </SOAP-ENV:Body> </SOAP-ENV:Envelope> 请问该怎么才能取到返回值？？谢谢.

Answer 1

    $client = new SoapClient($host, array(
        'trace' => true,
        'cache_wsdl' => WSDL_CACHE_BOTH,
    ));
    $functionName = 'funcname';
    $response = $client->__soapCall($functionName, array(
        $functionName => array('in0' => $params),
    ));

确认一下你的soap Server地址