php怎么这段字符串分割到数组

Question

HTTP/1.1 200 OK<br>Server: NWSs<br>Date: Sat, 02 Sep 2017 05:31:58 GMT<br>Content-Type: text/html; charset=utf-8<br>Content-Length: 4955<br>Connection: keep-alive<br>Cache-Control: max-age=86400<br>Expires: Sun, 03 Sep 2017 05:31:58 GMT<br>Last-Modified: Thu, 31 Aug 2017 08:29:39 GMT<br>Content-Encoding: gzip<br>X-NWS-LOG-UUID: b5d7cf9d-5d88-44ba-a6d0-411024e5ffc1<br>X-Cache-Lookup: Hit From MemCache Gz<br>Access-Control-Allow-Origin: *<br><br> 我需要分解成array("Server" => "NWSs", "Date" => "Sat, 02 Sep 2017 05:31:58 GMT"); 这样的！

Answer 1

$header = 'HTTP/1.1 200 OK<br>Server: NWSs<br>Date: Sat, 02 Sep 2017 05:31:58 GMT<br>Content-Type: text/html; charset=utf-8<br>Content-Length: 4955<br>Connection: keep-alive<br>Cache-Control: max-age=86400<br>Expires: Sun, 03 Sep 2017 05:31:58 GMT<br>Last-Modified: Thu, 31 Aug 2017 08:29:39 GMT<br>Content-Encoding: gzip<br>X-NWS-LOG-UUID: b5d7cf9d-5d88-44ba-a6d0-411024e5ffc1<br>X-Cache-Lookup: Hit From MemCache Gz<br>Access-Control-Allow-Origin: *<br><br>';

$header = explode('<br>', $header);

$method = array_shift($header);

$headers = [];

foreach ($header as $item) {
    preg_match_all("/(.*?): (.*)/", $item, $arr);
    if (!$arr[1][0] || !$arr[2][0]) {
        continue;
    }
    $headers[$arr[1][0]] = $arr[2][0];
}

纯手打，未验证。要是有错可以稍微改一下。大致上是这样。

Answer 2

别忘了 PHP 是一个合格的脚本语言，这些基本的功能实现起来是非常简单。今日得闲，帮你尝试一番，采用最基本的数组和字符串之间的转换和拼接，过程如下：

<?php 
$raw = 'HTTP/1.1 200 OK<br>Server: NWSs<br>Date: Sat, 02 Sep 2017 05:31:58 GMT<br>Content-Type: text/html; charset=utf-8<br>Content-Length: 4955<br>Connection: keep-alive<br>Cache-Control: max-age=86400<br>Expires: Sun, 03 Sep 2017 05:31:58 GMT<br>Last-Modified: Thu, 31 Aug 2017 08:29:39 GMT<br>Content-Encoding: gzip<br>X-NWS-LOG-UUID: b5d7cf9d-5d88-44ba-a6d0-411024e5ffc1<br>X-Cache-Lookup: Hit From MemCache Gz<br>Access-Control-Allow-Origin: *<br><br>';

// 以 <br> 为界初步分割为数组
$str = explode('<br>', $raw);

// 去除第一个无用元素 和 最后两个空元素
array_shift($str);
array_pop($str);
array_pop($str);

// 创建新数组用于储存拼接内容
$result = [];

foreach ($str as $key => $value) {
    $single = explode(':', $value);
    
    // 以下始拼接，防止被时间那组数据坑了
    // 获取新数组的关联
    $result_key = $single[0];
    // 去除关联，将剩余元素使用:接成为字符串
    array_shift($single);
    $result_value = implode(':', $single);
    // 储存处理好的内容
    $result = array_merge($result, ["$result_key" => "$result_value"]);
}

//输出结果
print_r($result);
?>

在 PHP 7.1.4 中，输出结果如下，基本满足题主的需求，并且避开了时间的坑：

Array
(
    [Server] =>  NWSs
    [Date] =>  Sat, 02 Sep 2017 05:31:58 GMT
    [Content-Type] =>  text/html; charset=utf-8
    [Content-Length] =>  4955
    [Connection] =>  keep-alive
    [Cache-Control] =>  max-age=86400
    [Expires] =>  Sun, 03 Sep 2017 05:31:58 GMT
    [Last-Modified] =>  Thu, 31 Aug 2017 08:29:39 GMT
    [Content-Encoding] =>  gzip
    [X-NWS-LOG-UUID] =>  b5d7cf9d-5d88-44ba-a6d0-411024e5ffc1
    [X-Cache-Lookup] =>  Hit From MemCache Gz
    [Access-Control-Allow-Origin] =>  *
)

综上所述，题目并不困难，只要肯思考肯定可以解决，题主可以封装为一个函数直接使用即可。唯一的小小小坑出现在时间分割处，注意克服即可。

Answer 3

先根据<'br'>分割出数组，array('HTTP/1.1 200 OK','Server: NWSs','Date: Sat, 02 Sep 2017 05:31:58 GMT','Content-Type: text/html; charset=utf-8',......),然后再做处理，拿出你想要的内容