SELECT from_unixtime(regtime, '%Y%m%d') dt , count(*) num from android_user group by dt order by dt desc limit 20;
SELECT from_unixtime(regtime, '%Y%m%d') dt , count(*) num from android_user where `parent_id` <> '' group by dt order by dt desc limit 20;
最后得到一张表,安日期分组,第二张图日期没有的num为0??求大神指导
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![?](http://img1.sycdn.imooc.com/545869470001a00302200220-100-100.jpg)
MM们
TA贡献1886条经验 获得超2个赞
SELECT from_unixtime(regtime, '%Y%m%d') dt , sum(case when parent_id='' then 0 else 1 end) num from android_user group by dt order by dt desc limit 20;
![?](http://img1.sycdn.imooc.com/545861b80001d27c02200220-100-100.jpg)
皈依舞
TA贡献1851条经验 获得超3个赞
你这个是一张表吧?可以使用一条sql语句呀。
SELECT from_unixtime(regtime, '%Y%m%d') dt , count(*) num from android_user where `parent_id` <> '' group by dt order by dt desc limit 20;
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