比如
$img = "/uploadfile/2018/03/12/2018031216434487207bw4i3u.jpg"
$content = '<p><img src="/uploadfile/2018/03/12/2018031216434487207bw4i3u.jpg" title="2018031216434487207bw4i3u.jpg" alt="04.jpg"/></p><p><br/><img style="MAX-WIDTH: 825px" title="2018020208575826654umwewz.jpg" alt="" src="/uploadfile/2018/02/02/2018020208575826654umwewz.jpg"/></p>'
怎么从$content里去掉包含$img图片
结果
$img = "/uploadfile/2018/03/12/2018031216434487207bw4i3u.jpg"
$content = '<p></p><p><br/><img style="MAX-WIDTH: 825px" title="2018020208575826654umwewz.jpg" alt="" src="/uploadfile/2018/02/02/2018020208575826654umwewz.jpg"/></p>'
1 回答
![?](http://img1.sycdn.imooc.com/53339fdf00019de902200220-100-100.jpg)
暮色呼如
TA贡献1853条经验 获得超9个赞
str_replace('src="'.$img.'"','',$content);
要是有单双引号的情况可以用
preg_replace("/ src=+[('|")s]+/uploadfile/2018/03/12/2018031216434487207bw4i3u.jpg+[('|")s]/",'',$content);
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