$selectTip = $pdo->query("SELECT * FROM `tips_rate`
WHERE `tip_id` = '".$row['id']."' "
);
$selecttotal = mysqli_num_rows($selectTip);
$rate = $pdo->query("SELECT SUM(star) as startotal FROM `tips_rate`
WHERE `tip_id` = '".$row['id']."' "
);
$startotal = mysqli_fetch_array($rate);
echo $startotal['startotal']/$selecttotal;
當我echo他們互除以的結果後假設沒有值他會出現NAN...能不能顯示 0?
1 回答
翻翻过去那场雪
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$num = $startotal['startotal']/$selecttotal;
echo is_nan($num) ? 0 : $num;
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