多选题评分算法 求指导

Question

多选题评分规则 每个正确选项都有得分权重，选正确一个给该正确选项得分权重的分值，选错一个，则总分为0 假如:正确答案ABC ，总分10分，权重分别为 20% 40% 40% 提交答案 ABC 得 （20%+40%+40%）* 10 = 10分 提交答案 AB 得 （20%+40%）* 10 = 6分 提交答案 ABD 得 0分 集思广益，如果可以请使用PHP作答

Answer 1

   function selectScore(preAnswerScore,answer) {
      let totalScore = 0;
      let noScoreKey = [];
      let hasNoScoreKey = false;
      for(let key in preAnswerScore) {
        if(preAnswerScore[key] == 0){
          noScoreKey.push(key);
        }
      }
      noScoreKey.map( item => {
        if(answer.includes(item)){
          hasNoScoreKey = true;
        }
      });
      if(hasNoScoreKey) {
        totalScore = 0;
      }else{
        answer.map (item => {
          totalScore += preAnswerScore[item];
        });
        totalScore /= 10;
      }
      return totalScore;
    } 
    let preAnswerScore = {a: 20, b: 40, c: 40, d: 0}; 
    let answer = ['c','b','d']
    console.log(selectScore(preAnswerScore, answer));
  }

js走一波，考虑到你其他选择题也适用

Answer 2

不会php， 用一下js

// 选择的选项
const select = ['a','b','d']
// 分数 
const score = {
    'a': 20,
    'b': 20,
    'c': 60,
    'd': 0
}
// 根据所选 得到 分数如：abd 的到 20,20,0
const a = select.map(x => score[x])
// 如果 a里面有 0 直接返回 0 否则 reduce 后得到 分数
total = a.includes(0) ? 0 : a.reduce((total, i) =>  total+ (i *0.1) , 0)

Answer 3

思路，获得提交与答案的交集，如果交集个数不等于提交个数，则认为，存在选错的值，如果交集个数等于提交个数，遍历求分即可

<?php

function multiSelectScore($answer, $wight, $allScore, $submit)
{
    $score = 0;
    $answerWight = array_combine($answer, $wight);
    // 计算交集
    $selects = array_intersect($answer, $submit);

    if(count($selects) === count($submit)) {
        // 遍历交集
        foreach($selects as $key => $select) {
            $score += $answerWight[$select] * 0.01 * $allScore;
        }
    }
    return $score;
}

// 答案
$answer = ["A", "B", "C"];
// 权重
$wight = ["20","30","50"];
// 总分
$allScore = 10;
// 提交的选项
$submit = ["A","C"];
$score = multiSelectScore($answer, $wight, $allScore, $submit);

echo json_encode($score) . "\n";

Answer 4

function calc($result,$answer,$score){
    $count = count($result);
    $d = array_diff($answer,$result);
    if($d){
        return  0;
    }
    $c = array_diff($result,$answer);
    $lost = count($c);
    if(!$lost){
         return  $score;
    }
    switch ($count) {
        case 1:
            $per = [1=>1];
            break;
        case 2:
            $per = [1=>0.4,2=>1];
            break;
        case 3:
            $per = [1=>0.2,2=>0.6,3=>1];
            break;
        default:
             $per = [1=>0.1,2=>0.5,3=>0.8,4=>1];
            break;
    }
    $true = $count - $lost ;
    return $per[$true]*$score;
    
}

$result = ['A','B','C'];
$answer = ['A','B'];
$score = 10;

echo calc($result,$answer,$score);

Answer 5

function check_score(array $answer, array $correct, $total_score){
    $answer=array_flip($answer);
    $check=array_intersect_key($correct, $answer);
    return in_array($check, 0) ? 0 : array_sum($ckeck)*$total_score;
}

$answer为答案数组（['A', 'B', 'C']）

$correct为正确答案数组（['A'=>0.2, 'B'=>0.4, 'C'=>0.4, 'D'=>0]）

$total_score为总分

首先翻转$answer让选项成为key（['A'=>0, 'B'=>1, 'C'=>2]）

然后根据key计算$correct和$answer的交集$check，$check的key和value都保留$correct的。

检查$check的value中是否有0，有的话说明有错误答案，返回0分，否则计算$check的value的和，并乘以总分返回。