jquery 返回实体对象怎么取值啊

Question

public String sayHello(){HttpServletResponse response=ServletActionContext.getResponse(); response.setContentType("text/html;charSet=gbk"); try {PrintWriter out = response.getWriter();Book book=new Book();book.setId(1);book.setIsbn("1234");book.setName("人中吕布");out.print(book);} catch (IOException e) {// TODO Auto-generated catch blocke.printStackTrace();} return null;}$(function(){$("input[type=button]:eq(0)").click(function(){var options = {type:"post",target: "#myTargetDiv",//dataType:'script',success: getsc};//ajax一步上传表单$("#myForm").ajaxSubmit(options);});});function getsc(data){//var obj = $(data);//var name = data.namealert($(data));/* 这几种都取不到..*/} 这是前台ajax提交,想取book对象的属性，应该怎么取啊?

Answer 1

如果你前面的配置没错的话:

function getsc(data)
{
var obj = $(data);
alert(obj.find("name").text());
}