HashMap的无参构造函数是如何构造初始容量为16的容器的？

Question

HashMap无参构造函数如下： /** * Constructs an empty <tt>HashMap</tt> with the default initial capacity * (16) and the default load factor (0.75). */ public HashMap() { this.loadFactor = DEFAULT_LOAD_FACTOR; // all other fields defaulted } 它是如何像它Javadoc中说的一样构造了一个初始容量为16的容器的？Node数组都不用初始化的么？至少加上一句 table = new Node<>[DEFAULT_INITIAL_CAPACITY]; 才合乎常理吧！请各位赐教！

Answer 1

注释说了在第一次使用的时候才会初始化

  /**
     * The table, initialized on first use, and resized as
     * necessary. When allocated, length is always a power of two.
     * (We also tolerate length zero in some operations to allow
     * bootstrapping mechanics that are currently not needed.)
     */
    transient Node<K,V>[] table;

初始化代码在 final Node<K,V>[] resize() 方法里面，

     Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
     table指向这个newTab