C#中自定义显式/隐式转换的问题

Question

在C#中如果定义显式/隐式转换是不是没有位置的要求，只要在任一类中定义了转换就可以？ 例如代码1和代码2木有区别咯？ 代码1 public class ConvClass1 { public int val; public static implicit operator ConvClass2(ConvClass1 op1) { ConvClass2 returnVal = new ConvClass2(); returnVal.val = op1.val; return returnVal; } public static implicit operator ConvClass1(ConvClass2 op1) { ConvClass1 returnVal = new ConvClass1(); checked { returnVal.val = (int)op1.val; } return returnVal; } } public class ConvClass2 { public double val; } 代码2 public class ConvClass1 { public int val; public static implicit operator ConvClass2(ConvClass1 op1) { ConvClass2 returnVal = new ConvClass2(); returnVal.val = op1.val; return returnVal; } } public class ConvClass2 { public double val; public static implicit operator ConvClass1(ConvClass2 op1) { ConvClass1 returnVal = new ConvClass1(); checked { returnVal.val = (int)op1.val; } return returnVal; } }

Answer 1

应该没区别吧