js正则表达式

Question

var str = "123456abc1abc";var re = /(\d+)(\D\D)/g;   //结果是["123456ab", "1ab"]// var re = /(\d+?)(\D\D)/g;  //结果是["123456ab", "1ab"] 这里非贪婪不应该是6ab 和 1ab吗console.log(str.match(re))

Answer 1

可以这么理解，没人要的东西你多要，不能叫做贪婪。

再举个栗子:

var str='1234abc56efg';

var regx1=/(\d+)(\d+)(\D\D)/g;

var regx2=/(\d+?)(\d+)(\D\D)/g;

console.log(regx1.exec(str)); // ["1234ab", "123", "4", "ab", index: 0, input: "1234abc56efg"]

console.log(regx2.exec(str)); // ["1234ab", "1", "234", "ab", index: 0, input: "1234abc56efg"]

注意匹配 $1 和匹配 $2 的值的区别