求解：[[1, 2], [3, 4]].map(([a, b]) => a + b); //

Question

// es6的函数参数的解构赋值[[1, 2], [3, 4]].map(([a, b]) => a + b);// [ 3, 7 ]

Answer 1

相当于这样

var arr1 = [1, 2];

var arr2 = [3, 4];

[arr1, arr2].map(arr => {

  var a = arr[0];

  var b = arr[1];

  return a + b;

});