Http://www.test.com/Photo_Success.aspx?params={nums:'" + num + "',category:'" + iAlbumId.ToString() + "'}&filenames=" + FileName
上面的这个URL如何获取params里的nums 和category的值。 谢了!
2 回答
温温酱
TA贡献1752条经验 获得超4个赞
用javascript 接收到params这个参数的值,然后把值用Eval()转换成JSON就可以获取 nums 和category的值
下面函数是获取地址栏值
function getUrlParams() {
var args = new Object();
var query = location.search.substring(1); // Get query string
var pairs = query.split("&"); // Break at ampersand
for (var i = 0; i < pairs.length; i++) {
var pos = pairs[i].indexOf('='); // Look for "name=value"
if (pos == -1) continue; // If not found, skip
var argname = pairs[i].substring(0, pos); // Extract the name
var value = pairs[i].substring(pos + 1); // Extract the value
value = decodeURIComponent(value); // Decode it, if needed
args[argname] = value; // Store as a property
}
return args;
}
var Params = getUrlParams()["params"];
var object_op = eval(Params);
var nums = object_op.object_op ;
var category = object_op.category;
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