如何切割这个数组？

Question

        var curhour = new Date().getHours();        var hourList = ['8:00-9:00', '9:00-10:00', '10:00-11:00', '11:00-12:00', '12:00-13:00', '13:00-14:00', '14:00-15:00', '15:00-16:00', '16:00-17:00', '17:00-18:00', '18:00-19:00','19:00-20:00']一个预约服务的需求，怎么比较如何返回当前时间（12点）两个小时以后的数组,接受预约服务的营业时间为8-19点；['14:00-15:00', '15:00-16:00', '16:00-17:00', '17:00-18:00', '18:00-19:00','19:00-20:00']

Answer 1

        var curhour = new Date().getHours();

        var hourList = ['8:00-9:00', '9:00-10:00', '10:00-11:00', '11:00-12:00', '12:00-13:00', '13:00-14:00', '14:00-15:00', '15:00-16:00', '16:00-17:00', '17:00-18:00', '18:00-19:00','19:00-20:00'];

        var resultHourList;

        var foundIndex=hourList.findIndex(function(item){

            var start=parseInt(item.split("-")[0].split(":")[0],10);

            if(start===curhour){

                return true;

            }else{

                return false;

            }

        });

        

        if(foundIndex!=-1){

            resultHourList=hourList.splice(foundIndex);

        }

        

        console.log(resultHourList);

或者

        var curhour = new Date().getHours();

        var hourList = ['8:00-9:00', '9:00-10:00', '10:00-11:00', '11:00-12:00', '12:00-13:00', '13:00-14:00', '14:00-15:00', '15:00-16:00', '16:00-17:00', '17:00-18:00', '18:00-19:00','19:00-20:00'];

        var resultHourList;

        var firstHour=parseInt(hourList[0].split("-")[0].split(":")[0],10);

        var offset=curhour-firstHour;

        resultHourList=hourList.splice(offset);

        console.log(resultHourList);