将函数的继承封装成如下函数:function extend(child, parent){ var f = function(){}
f.prototype = parent.prototype
child.prototype = new f()
child.prototype.constructor = child
child.uber = parent.prototype}
function Creature(){}
function Person(){}extend(Person, Creature)请教一下,这是访问Person.uber属性,为什么是undefined?
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