下面的数据想用递归或其实灵活的方法把他实现成下面的最终结果要怎么实现？？？
1 回答
哈士奇WWW
TA贡献1799条经验 获得超6个赞
直接上代码~
<html>
<script src="jquery.min.js"></script>
<body>
<script>
var menus = [];
var temp = {
"value":[
{
"subMenus":[],
"menuName":"一级",
"clickUrl":"/",
},
{
"menuName":"一级",
"subMenus":[{
"subMenus":[],
"clickUrl":"/two/a",
"menuName":"二级",
},{
"subMenus":[],
"clickUrl":"/two/b",
"menuName":"二级",
}]
}
]
};
function changeJson(temp){
var tempMenus = [];
for(var i = 0; i < temp.length; i ++){
tempMenus.push({});
var menuItem = tempMenus[i];
menuItem.title = temp[i].menuName;
menuItem.path = temp[i].clickUrl;
if(temp[i].subMenus.length > 0){
menuItem.children = changeJson(temp[i].subMenus);
}else{
menuItem.children = [];
}
}
return tempMenus;
}
console.log(changeJson(temp.value));
</script>
</body>
</html>
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